Armstrong Number in Java

 Check if the given number is an Armstrong Number or not in Java.

package Interview;

 

import java.util.Arrays;

 

public class ArmstrongNumber {

 

       public static void main(String[] args) {

            

             //153 is an Armstrong Number as 153= 1+ 125+27 which comes from 1^3+5^3+3^3

            

             int givenNum = 9474;

             String givenNumStr = Integer.toString(givenNum);

             int len = givenNumStr.length();

             int[] numArr = new int[len];//To put each individual integer

             int[] numArr1 = new int[len];//To put each individual calculated value

             int calculatedNum =0;

             for(int i=0;i<len;i++) {

                    numArr[i]=Integer.parseInt(Character.toString(givenNumStr.charAt(i)));

                    numArr1[i]= (int) Math.pow(numArr[i], len) ;

                    calculatedNum = numArr1[i]+calculatedNum;

             }

             System.out.println("Each individual digit: "+Arrays.toString(numArr));

             System.out.println("Each individual calculated value: "+Arrays.toString(numArr1));

             System.out.println("Sum of calculated values: "+calculatedNum);

            

             if (calculatedNum==givenNum) {

                    System.out.println(givenNum+" is an Armstrong Number");

             } else {

                    System.out.println(givenNum+" is NOT an Armstrong Number");

             }

       }

 

}

 

Output:

Each individual digit: [9, 4, 7, 4]

Each individual calculated value: [6561, 256, 2401, 256]

Sum of calculated values: 9474

9474 is an Armstrong Number