"Like with %" , this is used to search the data from table with incomplete column name.
For example:
Name | Dept | Salary | comm | State |
Ram | Technical | 1000 | null | TX |
Sam | Admin | 1100 | null | CA |
Hari | Mechanical | 1200 | null | TX |
Raju | Helper | 800 | 800 | TX |
Govind | HR | 1000 | null | CA |
Murali | Driver | 900 | null | NY |
Murali1 | DHead | null | null | NY |
Sita | Actor | 1400 | 111 | TX |
1.
1. 1. select * from TableUnitTest where name like '%nd';
Name Dept Salary comm State
Govind HR 1000 null CA
2. 2. select * from TableUnitTest where name like 'nd%';
No result.
3. 3. select * from TableUnitTest where name like '%nd%';
Name Dept Salary comm State
Govind HR 1000 null CA
4. 4. select * from TableUnitTest where name like 'R%';
Name Dept Salary comm State
Ram Technical 1000 null TX
Raju Helper 800 800 TX
5. 5. select * from TableUnitTest where name like '%R%';
Name Dept Salary comm State
Ram Technical 1000 null TX
Hari Mechanical 1200 null TX
Raju Helper 800 800 TX
Murali Driver 900 null NY
Murali1 DHead null null NY
6. 6. select * from TableUnitTest where salary like '%2%' ;
Name Dept Salary comm State
Hari Mechanical 1200 null TX
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